#kryptos #morse #aivirai

I would like to share some information about **#Kryptos **that I haven`t seen anywhere yet, and I strongly believe will **lead someone to final solution** (as always):)

First one that I wanted to share is connected to the idea that Mr. Sanborn could easily **deceive us** and make decryption a bit more difficult, even without the knowledge of any advanced math or crypto algorithms by himself.

**The idea is following (in pseudo-code):**

`Input:`

1) zeros_and_ones: string of 0 and 1

2) plain_text: plain text to encrypt

2) key: key

3) basic_algorithm: selected cryptography algorithm which uses key. algorithm has two methods:

3.1) basic_algorithm.encrypt(position, letter, key)

3.2) basic_algorithm.decrypt(position, letter, key)

**The idea for new_algorithm is following:**

`new_algorithm.encrypt(zeros_and_ones, position, plain_text, key):`

letter = plain_text[position]

if (zeros_and_ones[position] == 0):

return basic_algorithm.encrypt(position, letter, key)

else:

return basic_algorithm.decrypt(position, letter, key)

**similar approach to decryption:**

`new_algorithm.decrypt(zeros_and_ones, position, encrypted_text, key):`

letter = encrypted_text[position]

if (zeros_and_ones[position] == 1):

return basic_algorithm.encrypt(position, letter, key)

else:

return basic_algorithm.decrypt(position, letter, key)

To sum up in one sentence: it says that in order to produce encrypted letter you either must encrypt it or decrypt – which approach to use is based on the zeros_and_ones string

Why did I write about this idea?

If you get the top rows from morse code:

`E DIGETAL EEE`

T IS YOUR

EE VIRTUALLY E

EE SHADOW EE

LUCID EEE

remove the debris (Es)`DIGETAL`

T IS YOUR

VIRTUALLY

SHADOW

LUCID

correct the mistake (DIGETAL -> DIGITAL) and you have exactly 97 zeros and ones (dashes and dots in morse code).

This leads us to Part II (soon).

Greg.