still working on this pattern, but not found anything interesting
before/after AGENCIES and SYMBOL until now. The Creator is not accepting
partial solutions, so no constructive response acquired. I`ve tried to
look for something interesting near BLETCHLEY PARK and … UNITED
KINGDOM is found.
A couple of months ago I decided not to touch K4 until the next clue is given. (Un-)fortunately I did not keep my word.
I decided that I would like to learn something new. This time: Python. Great language. I also decided to try to write something that I have not written yet. I decided to test K4 possiblities of words from another perspective.
What are K4 possiblities of words? Basically these are words that are possible to get from K4 decryption using known encryption algorithm and unknown masking technique.
Until now I tried to find some patterns using method based on:
select long_word from K4 possibilities
try to find some pattern between long_word and BC (comparing decrypted and encrypted text)
This time I thought that I will use Python instead of Java and I will try something else.
I tried something like:
from collections import Counter from pandas import DataFrame
read source data:
possibilitiesFile = ".\\k4_possibilities_of_words_on_positions_from_amartia.txt" enc = 'utf-8'
srcFile = ".\\cryptography_book_dump.txt"
with open(srcFile, 'r', encoding = enc) as myfile:
raw_data = [myfile.read()]
clean data from the book and remove short words:
whitelist = set('abcdefghijklmnopqrstuvwxyz ABCDEFGHIJKLMNOPQRSTUVWXYZ')
clean_data = [ ' '.join(w for w in ''.join(filter(whitelist.__contains__, msg)).lower().split() if len(w)>3) for msg in raw_data]
read data from K4 possibilities:
with open(possibilitiesFile, 'r', encoding = enc) as myfile:
raw_possibilities = myfile.readlines()
clean_possibilities = [line.rstrip().split(';') for line in raw_possibilities]
selected = [bigram for bigram in new_bigrams if counter_bigrams[bigram] > 0 and len(bigram + bigram) > 9 and (len(bigram) > 5 or len(bigram) > 5)]
common = ['with', 'like', 'this']
selected2 = [bigram for bigram in selected if bigram not in common and bigram not in common]
As I mentioned before, I promised myself not to touch K4 until the next clue is given. I did not keep my word.
print(selected) ('turing', 'alan')
and now the horror begins again. I thought I am free of this curse.